# -*- coding: UTF-8 -*- import cv2 import time import numpy as np import skimage.exposure ''' 两个区域间最短距离 https://www.cnpython.com/qa/1329750 ''' import math def downsample(num_arr,downsample_rate): ''' 下采样数组,隔着downsample_rate个数取一个值 num_arr为数组 downsample_rate为采用概率,为1-n的正整数 ''' num_arr_temp=[] for i in range(len(num_arr)//downsample_rate-1): num_arr_temp.append(num_arr[i*downsample_rate]) return num_arr_temp def array_distance(arr1,arr2): ''' 计算两个数组中,每任意两个点之间L2距离 arr1和arr2都必须是numpy数组 且维度分别是mx2,nx2 输出数组维度为mxn ''' m,_=arr1.shape n,_=arr2.shape arr1_power = np.power(arr1, 2) xxx=arr1_power[:, 0] arr1_power_sum = arr1_power[:, 0] + arr1_power[:, 1] #第1区域,x与y的平方和 yyy=arr1_power_sum arr1_power_sum = np.tile(arr1_power_sum, (n, 1)) #将arr1_power_sum沿着y轴复制n倍,沿着x轴复制1倍,这里用于与arr2进行计算。 nxm 维度 zzz=arr1_power_sum arr1_power_sum = arr1_power_sum.T #将arr1_power_sum进行转置 arr2_power = np.power(arr2, 2) arr2_power_sum = arr2_power[:, 0] + arr2_power[:, 1] #第2区域,x与y的平方和 arr2_power_sum = np.tile(arr2_power_sum, (m, 1)) #将arr1_power_sum沿着y轴复制m倍,沿着x轴复制1倍,这里用于与arr1进行计算。 mxn 维度 dis = arr1_power_sum + arr2_power_sum - (2 * np.dot(arr1, arr2.T)) #np.dot(arr1, arr2.T)矩阵相乘,得到xy的值。 dis = np.sqrt(dis) return dis # 中间输入的代码 # 将数组存在num_arr1和num_arr2中 t1=time.time() # 1.读入图片 # img = cv2.imread('demo/171.png') img = cv2.imread('demo/9.png') t2=time.time() img_gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY) contours, thresh = cv2.threshold(img_gray, 0, 255, cv2.THRESH_BINARY + cv2.THRESH_OTSU) # 2.寻找轮廓(多边界) contours, hierarchy = cv2.findContours(thresh, cv2.RETR_LIST, 2) # 3.轮廓数组转为列表(多边界) list_contours=[] record=[] num_arr1=contours[0] num_arr2=contours[1] ssss1=np.squeeze(num_arr1, 1) ssss2=np.squeeze(num_arr2, 1) # 3.对边界进行下采样,减小点数量。 num_arr11=downsample(num_arr1,10) #下采样边界点 num_arr22=downsample(num_arr2,10) #下采样边界点 print(num_arr1) t3=time.time() dist_arr=array_distance(ssss1,ssss2) min_dist=dist_arr[dist_arr>0].min() print(min_dist) # print('两区域最小距离',min(record)) t4=time.time() print('读图时间:%s 找边界时间:%s 区域最短距离计算时间:%s'%(t2-t1,t3-t2,t4-t3))